{"id":18377,"date":"2024-04-16T17:23:21","date_gmt":"2024-04-16T17:23:21","guid":{"rendered":"https:\/\/soicau4074.minhngocxoso.com\/?p=18377"},"modified":"2024-04-16T17:23:21","modified_gmt":"2024-04-16T17:23:21","slug":"cach-tinh-xac-suat-lo-de-chinh-xac-nhat","status":"publish","type":"post","link":"https:\/\/bachthulodep.com\/cach-tinh-xac-suat-lo-de-chinh-xac-nhat\/","title":{"rendered":"c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c nh\u1ea5t"},"content":{"rendered":"
\u0110\u00e1nh l\u00f4 \u0111\u1ec1, ch\u00fang ta kh\u00f4ng th\u1ec3 \u0111\u00e1nh cho c\u00f3. Kh\u00f4ng \u0111\u01b0\u1ee3c \u0111\u00e1nh theo ki\u1ec3u th\u00edch th\u00ec \u0111\u00e1nh, th\u00edch con n\u00e0o \u0111\u00e1nh con \u0111\u00f3. Nh\u01b0 v\u1eady kh\u00f4ng hi\u1ec7u qu\u1ea3, m\u00e0 ch\u1ec9 ti\u1ec1n m\u1ea5t m\u00e0 th\u00f4i.<\/p>\n
Ch\u00ednh v\u00ec v\u1eady, c\u00e1c b\u1ea1n c\u1ea7n ph\u1ea3i xem b\u00e0i n\u00e0y nhi\u1ec1u l\u1ea7n. \u0110\u1ec3 hi\u1ec3u r\u00f5 c\u00e1ch s\u1ed1 \u0111\u1ec1 ho\u1ea1t \u0111\u1ed9ng v\u00e0 t\u1ec9 l\u1ec7 tr\u00fang c\u1ee7a \u0111\u00e1nh l\u00f4, \u0111\u00e1nh \u0111\u1ec1 l\u00e0 bao nhi\u00eau %. C\u00f2n nhi\u1ec1u \u0111i\u1ec1u th\u00fa v\u1ecb \u1edf b\u00ean d\u01b0\u1edbi, m\u1eddi c\u00e1c b\u1ea1n c\u00f9ng theo d\u00f5i nh\u00e9.<\/p>\n
V\u1edbi \u0110\u1ec1 th\u00ec c\u00f3 l\u1ebd nhi\u1ec1u b\u1ea1n bi\u1ebft r\u1ed3i. T\u00ednh x\u00e1c su\u1ea5t \u0111\u1ec3 tr\u00fang 1 con \u0111\u1ec1 l\u00e0 1\/100 = 1%<\/strong> m\u00e0 th\u00f4i.<\/p>\n Ch\u00fang ta kh\u00f4ng n\u00f3i \u0111\u1ebfn vi\u1ec7c tr\u00fang m\u1ea5y nh\u00e1y. Ch\u00fang ta ch\u1ec9 n\u00f3i l\u00e0 Tr\u00fang L\u00f4 nh\u00e9.<\/p>\n T\u00ednh x\u00e1c su\u1ea5t \u0111\u1ec3 tr\u00fang L\u00f4 = 1 \u2013 (x\u00e1c su\u1ea5t t\u1ea1ch l\u00f4) = 1 \u2013 0,99^27 (quay 27 s\u1ed1 \u0111\u1ec1u tr\u01b0\u1ee3t) = 23,7657 %<\/strong>.<\/p>\n <\/p>\n Ch\u00fang ta s\u1ebd c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p cho L\u00f4 Xi\u00ean 2 l\u00e0: Ch\u1ec9 v\u1ec1 1 con<\/strong> v\u00e0 kh\u00f4ng v\u1ec1 c\u1ea3 2 con<\/strong>.<\/p>\n X\u00e1c Su\u1ea5t \u0111\u1ec3 kh\u00f4ng v\u1ec1 c\u1ea3 2 con<\/strong> s\u1ebd = 0,98^27 = 57,957 %.<\/p>\n T\u00ednh X\u00e1c Su\u1ea5t ch\u1ec9 v\u1ec1 1 con<\/strong>: \u1ede \u0111\u00e2y ch\u00fang ta s\u1ebd c\u00f3 2 tr\u01b0\u1eddng h\u1ee3p l\u00e0: Con th\u1ee9 nh\u1ea5t v\u1ec1 v\u00e0 con th\u1ee9 2 kh\u00f4ng v\u1ec1. Con th\u1ee9 2 v\u1ec1 v\u00e0 con th\u1ee9 nh\u1ea5t kh\u00f4ng v\u1ec1. Nh\u01b0 v\u1eady, X\u00e1c Su\u1ea5t ch\u1ec9 v\u1ec1 1 con s\u1ebd = 2 * x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4 * x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 = 2 * 23,7657% * 0,99^27 = 36,238%.<\/p>\n T\u00ednh X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2 <\/b>= X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con = 57,957% + 36,238% = 94,195%.<\/p>\n T\u00ednh X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2 <\/b>= 100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang = 100 \u2013 94,195% = 5,8%<\/strong>.<\/p>\n C\u0169ng nh\u01b0 c\u00e1ch t\u00ednh c\u1ee7a L\u00f4 Xi\u00ean 2 b\u00ean tr\u00ean. Nh\u01b0ng \u1edf \u0111\u00e2y l\u00e0 Xi\u00ean 3 n\u00ean s\u1ebd t\u00ednh l\u00e2u h\u01a1n. C\u00e1ch t\u00ednh v\u1eabn t\u01b0\u01a1ng t\u1ef1 nh\u01b0 L\u00f4 Xi\u00ean 2.<\/p>\n T\u00ednh X\u00e1c Su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3<\/b> = X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 con = 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%.<\/p>\n => X\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/b> = 100% \u2013 98,527% = 1,473%<\/strong> ( ch\u1ec9 d\u1ec5 h\u01a1n tr\u00fang \u0111\u1ec1 1 t\u00fd).<\/p>\n <\/p>\n X\u00e1c xu\u1ea5t tr\u00fang \u0111\u1ec1 3 ch\u00e2n<\/strong> th\u00ec ai c\u0169ng bi\u1ebft \u0111\u1ec3 tr\u00fang \u0111\u1ec1 3 ch\u00e2n l\u00e0 1\/1000 = 0,1 %. C\u1ef1c k\u1ef3 kh\u00f3, ph\u1ea3i d\u1ef1a v\u00e0o may m\u1eafn nhi\u1ec1u.<\/p>\n X\u00e1c xu\u1ea5t tr\u00fang l\u00f4 3 ch\u00e2n<\/strong> = 1 \u2013 x\u00e1c xu\u1ea5t t\u1ea1ch l\u00f4 3 ch\u00e2n = 1 \u2013 0,999^27 = 2,67 %. <\/strong>C\u0169ng r\u1ea5t kh\u00f3.<\/p>\n L\u00f4 \u0110\u1ec1<\/strong> ch\u01b0a bao gi\u1edd \u0111\u01a1n gi\u1ea3n. Ch\u00fang ta \u0111\u00e1nh l\u00f4 \u0111\u1ec1 kh\u00f4ng th\u1ec3 d\u1ef1a v\u00e0o suy \u0111o\u00e1n m\u00e0 c\u1ea7n ph\u1ea3i T\u00ednh To\u00e1n k\u1ef9 l\u01b0\u1ee1ng. M\u1ed7i ng\u00e0y, ch\u00fang t\u00f4i d\u00e0nh ra h\u01a1n 5 ti\u1ebfng \u0111\u1ec3 soi c\u1ea7u, ch\u1ed1t s\u1ed1, ph\u00e2n t\u00edch. Sau \u0111\u00f3 m\u1edbi xu\u1ed1ng ti\u1ec1n \u0111\u00e1nh l\u00f4 \u0111\u1ec1. Th\u1ef1c s\u1ef1 ch\u01b0a bao gi\u1edd \u0111\u01a1n gi\u1ea3n n\u1ebfu nh\u01b0 mu\u1ed1n tr\u00fang L\u00f4 \u0110\u1ec1.<\/p>\n C\u00e1c c\u1eb7p s\u1ed1 \u0111\u1eb9p nh\u1ea5t h\u00e0ng ng\u00e0y \u0111\u01b0\u1ee3c ch\u00fang t\u00f4i chia s\u1ebb trong chuy\u00ean m\u1ee5c Ch<\/strong><\/p>\n \u00a0ch\u1ed1t s\u1ed1 soi c\u1ea7u b\u1ea1ch th\u1ee7 l\u00f4 2 nh\u00e1y mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n \u00a0ch\u1ed1t s\u1ed1 soi c\u1ea7u b\u1ea1ch th\u1ee7 l\u00f4 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u song th\u1ee7 l\u00f4 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u b\u1ea1ch th\u1ee7 l\u00f4 k\u00e9p mb<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u song th\u1ee7 l\u00f4 k\u00e9p mb<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u b\u1ea1ch th\u1ee7 \u0111\u1ec1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u song th\u1ee7 \u0111\u1ec1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n \u0111\u1ec1 4 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n \u0111\u1ec1 6 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n \u0111\u1ec1 8 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n \u0111\u1ec1 10 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 4 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/span><\/p>\n \u00a0ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 6 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 8 s\u1ed1 mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 xi\u00ean 2 mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 xi\u00ean 3 mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 xi\u00ean 4 mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u 3 c\u00e0ng mi\u1ec1n b\u1eafc<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n 3 c\u00e0ng 2 s\u1ed1 mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u d\u00e0n l\u00f4 10 s\u1ed1 mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u \u0111\u1ec1 \u0111\u1ea7u \u0111u\u00f4i mb<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u x\u1ec9u ch\u1ee7 mi\u1ec1n nam<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mn<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u gi\u1ea3i 8 mi\u1ec1n nam<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u bao l\u00f4 mi\u1ec1n nam<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u c\u1eb7p x\u1ec9u ch\u1ee7 mn<\/strong><\/span><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u song th\u1ee7 l\u00f4 mn<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u \u0111\u1ea7u \u0111u\u00f4i gi\u1ea3i 8 mn<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u \u0111\u1ea7u \u0111u\u00f4i \u0111\u1eb7c bi\u1ec7t mn<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u l\u00f4 3 s\u1ed1 mi\u1ec1n nam<\/span><\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u x\u1ec9u ch\u1ee7 mi\u1ec1n trung<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n trung<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u to gi\u1ea3i 8 mi\u1ec1n trung<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u bao l\u00f4 mi\u1ec1n trung<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u c\u1eb7p x\u1ec9u ch\u1ee7 mi\u1ec1n trung<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u song th\u1ee7 l\u00f4 mt<\/strong><\/a><\/p>\n ch\u1ed1t s\u1ed1 soi c\u1ea7u \u0111\u1ea7u \u0111u\u00f4i gi\u1ea3i 8 mt<\/strong><\/a><\/p>\nT\u00ednh X\u00e1c Su\u1ea5t Tr\u00fang L\u00f4 l\u00e0 bao nhi\u00eau ?<\/h2>\n
T\u00ednh X\u00e1c Su\u1ea5t Tr\u00fang L\u00f4 Xi\u00ean 2 l\u00e0 bao nhi\u00eau ?<\/h2>\n
T\u00ednh X\u00e1c Su\u1ea5t Tr\u00fang L\u00f4 Xi\u00ean 3 l\u00e0 bao nhi\u00eau ?<\/h2>\n
T\u00ednh X\u00e1c Su\u1ea5t Tr\u00fang \u0110\u1ec1 2 Ch\u00e2n v\u00e0 L\u00f4 3 Ch\u00e2n l\u00e0 bao nhi\u00eau ?<\/h2>\n
K\u1ebft Th\u00fac<\/h2>\n
.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span>\u00a0c\u1ea7u ch\u1ed1t s\u1ed1 xs mi\u1ec1n b\u1eafc si\u00eau c\u1ea5p\u00a0.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span><\/strong><\/h3>\n
\n.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span>\u00a0c\u1ea7u ch\u1ed1t s\u1ed1 xs mi\u1ec1n b\u1eafc v\u00edp\u00a0.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span><\/strong><\/h3>\n
\n.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span>\u00a0ch\u1ed1t s\u1ed1 soi c\u1ea7u xs mi\u1ec1n nam\u00a0.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span><\/strong><\/h3>\n
\n.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span>\u00a0ch\u1ed1t s\u1ed1 soi c\u1ea7u xs mi\u1ec1n trung\u00a0.\u00b0 \u00ba \u273f \u00ba \u00b0<\/span><\/strong><\/h3>\n
\n