L\u00f4 tr\u01b0\u1ee3t l\u00e0 g\u00ec?<\/strong><\/h3>\nTheo kinh nghi\u1ec7m c\u1ee7a nh\u1eefng ng\u01b0\u1eddi nghi\u00ean c\u1ee9u l\u00f4 \u0111\u1ec1, l\u00f4 tr\u01b0\u1ee3t \u0111\u01b0\u1ee3c hi\u1ec3u n\u00f4m na l\u00e0 \u0111\u00e1nh l\u00f4 theo nh\u1eefng c\u1eb7p s\u1ed1 kh\u00f4ng v\u1ec1, trong tr\u01b0\u1eddng h\u1ee3p mu\u1ed1n ch\u01a1i l\u00f4 tr\u01b0\u1ee3t b\u1eb1ng nh\u1eefng con l\u00f4 khan, l\u00f4 gan l\u00ec l\u00e0 v\u00f4 l\u00fd t\u01b0\u1edfng.<\/p>\n
C\u00f3 th\u1ec3 nhi\u1ec1u ng\u01b0\u1eddi \u0111\u00e3 t\u1eebng bi\u1ebft v\u1ec1 l\u00f4 tr\u01b0\u1ee3t nh\u01b0ng c\u00e1ch b\u1eaft l\u00f4 tr\u01b0\u1ee3t hi\u1ec7u qu\u1ea3 v\u00e0 ch\u1eafc \u0103n th\u00ec kh\u00f4ng ph\u1ea3i ai c\u0169ng bi\u1ebft r\u00f5 \u0111\u01b0\u1ee3c. N\u1ebfu b\u1ea1n \u0111ang quan t\u00e2m t\u1edbi v\u1ea5n \u0111\u1ec1 n\u00e0y, th\u00ec h\u00e3y tham kh\u1ea3o 2 c\u00e1ch soi c\u1ea7u l\u00f4 tr\u01b0\u1ee3t b\u00ean d\u01b0\u1edbi nh\u00e9.<\/b><\/p>\nHai c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t hi\u1ec7u qu\u1ea3.<\/strong><\/h3>\n<\/p>\n
L\u00e0 2 c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t<\/strong> \u0111\u01b0\u1ee3c ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u nghi\u00ean c\u1ee9u v\u00e0 chia s\u1ebd cho anh em th\u00edch ch\u01a1i l\u00f4 \u0111\u1ec1 tham kh\u1ea3o, anh em c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t n\u00e0y \u0111\u1ec3 t\u00ecm ra l\u00f4 tr\u00fang.<\/p>\nC\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t 1.<\/strong><\/h4>\nNh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00f4 tr\u01b0\u1ee3t hay l\u00f4 tr\u01b0\u1ee3t mi\u1ec1n B\u1eafc ng\u01b0\u1eddi ch\u01a1i s\u1ebd ph\u1ea3i ch\u1ecdn xi\u00ean 4, xi\u00ean 8, xi\u00ean 10 v\u00e0 n\u1ebfu c\u00f3 th\u00ec c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec:<\/p>\n
\n- \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/li>\n
- C\u1ea3 8 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 7.<\/li>\n
- 10 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 10.<\/li>\n<\/ul>\n
X\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 theo c\u00e1ch xi\u00ean 4, xi\u00ean 8 hay xi\u00ean 10 s\u1ebd cho ta bi\u1ebft nh\u1eefng c\u01a1 h\u1ed9i ki\u1ebfm ti\u1ec1n, cho n\u00ean ch\u00fang ta c\u1ea7n l\u00e0m r\u00f5 con s\u1ed1 n\u00e0y.<\/p>\n
V\u00e0 x\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t c\u1ee7a 1 con l\u00e0 78%, tuy l\u00f4 tr\u01b0\u1ee3t c\u00f3 27 gi\u1ea3i nh\u01b0ng ch\u1ec9 c\u00f3 b\u00ecnh qu\u00e2n 21,5 \u2013 22 s\u1ed1 kh\u00e1c nhau => trong 100 s\u1ed1 th\u00ec c\u00f3 \u0111\u1ebfn 78 s\u1ed1 l\u00e0 tr\u01b0\u1ee3t => x\u00e1c su\u1ea5t \u0111\u1ec3 ch\u1ecdn 1 l\u00f4 tr\u01b0\u1ee3t = 78%. T\u1eeb \u0111\u00f3 ta c\u00f3 th\u1ec3 suy ra.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 4: 0,78\u00d70,78\u00d70,78\u00d70,78 = 0,37, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 37% khi c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/p>\n
L\u01b0u \u00fd<\/strong>: x\u00e1c xu\u1ea5t \u0111\u00e1nh b\u1ea1ch th\u1ee7 tr\u00fang 1 con l\u00f4 l\u00e0 22%, nh\u01b0ng Ti\u1ec1n thu v\u1ec1 = 3,5 Ti\u1ec1n chi ra, ch\u1ee9 kh\u00f4ng ph\u1ea3i ch\u1ec9 \u0103n 2 l\u1ea7n. C\u00e1c b\u1ea1n c\u0169ng n\u00ean ph\u00e2n bi\u1ec7t x\u00e1c su\u1ea5t tr\u00fang v\u1edbi t\u1ef7 l\u1ec7 \u0103n ti\u1ec1n.<\/p>\n\u2013 L\u00f4 tr\u01b0\u1ee3t xi\u00ean 8: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 = 0,14, t\u01b0\u01a1ng \u1ee9ng v\u1eady x\u00e1c su\u1ea5t \u0103n l\u00e0 14% , gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 10: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 x0,78\u00d70,78 = 0,083, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 8,3%, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
Hai c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t hi\u1ec7u qu\u1ea3.<\/strong><\/h3>\n<\/p>\n
L\u00e0 2 c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t<\/strong> \u0111\u01b0\u1ee3c ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u nghi\u00ean c\u1ee9u v\u00e0 chia s\u1ebd cho anh em th\u00edch ch\u01a1i l\u00f4 \u0111\u1ec1 tham kh\u1ea3o, anh em c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o c\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t n\u00e0y \u0111\u1ec3 t\u00ecm ra l\u00f4 tr\u00fang.<\/p>\nC\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t 1.<\/strong><\/h4>\nNh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00f4 tr\u01b0\u1ee3t hay l\u00f4 tr\u01b0\u1ee3t mi\u1ec1n B\u1eafc ng\u01b0\u1eddi ch\u01a1i s\u1ebd ph\u1ea3i ch\u1ecdn xi\u00ean 4, xi\u00ean 8, xi\u00ean 10 v\u00e0 n\u1ebfu c\u00f3 th\u00ec c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec:<\/p>\n
\n- \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/li>\n
- C\u1ea3 8 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 7.<\/li>\n
- 10 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 10.<\/li>\n<\/ul>\n
X\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 theo c\u00e1ch xi\u00ean 4, xi\u00ean 8 hay xi\u00ean 10 s\u1ebd cho ta bi\u1ebft nh\u1eefng c\u01a1 h\u1ed9i ki\u1ebfm ti\u1ec1n, cho n\u00ean ch\u00fang ta c\u1ea7n l\u00e0m r\u00f5 con s\u1ed1 n\u00e0y.<\/p>\n
V\u00e0 x\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t c\u1ee7a 1 con l\u00e0 78%, tuy l\u00f4 tr\u01b0\u1ee3t c\u00f3 27 gi\u1ea3i nh\u01b0ng ch\u1ec9 c\u00f3 b\u00ecnh qu\u00e2n 21,5 \u2013 22 s\u1ed1 kh\u00e1c nhau => trong 100 s\u1ed1 th\u00ec c\u00f3 \u0111\u1ebfn 78 s\u1ed1 l\u00e0 tr\u01b0\u1ee3t => x\u00e1c su\u1ea5t \u0111\u1ec3 ch\u1ecdn 1 l\u00f4 tr\u01b0\u1ee3t = 78%. T\u1eeb \u0111\u00f3 ta c\u00f3 th\u1ec3 suy ra.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 4: 0,78\u00d70,78\u00d70,78\u00d70,78 = 0,37, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 37% khi c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/p>\n
L\u01b0u \u00fd<\/strong>: x\u00e1c xu\u1ea5t \u0111\u00e1nh b\u1ea1ch th\u1ee7 tr\u00fang 1 con l\u00f4 l\u00e0 22%, nh\u01b0ng Ti\u1ec1n thu v\u1ec1 = 3,5 Ti\u1ec1n chi ra, ch\u1ee9 kh\u00f4ng ph\u1ea3i ch\u1ec9 \u0103n 2 l\u1ea7n. C\u00e1c b\u1ea1n c\u0169ng n\u00ean ph\u00e2n bi\u1ec7t x\u00e1c su\u1ea5t tr\u00fang v\u1edbi t\u1ef7 l\u1ec7 \u0103n ti\u1ec1n.<\/p>\n\u2013 L\u00f4 tr\u01b0\u1ee3t xi\u00ean 8: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 = 0,14, t\u01b0\u01a1ng \u1ee9ng v\u1eady x\u00e1c su\u1ea5t \u0103n l\u00e0 14% , gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 10: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 x0,78\u00d70,78 = 0,083, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 8,3%, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
C\u00e1ch \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t 1.<\/strong><\/h4>\nNh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00f4 tr\u01b0\u1ee3t hay l\u00f4 tr\u01b0\u1ee3t mi\u1ec1n B\u1eafc ng\u01b0\u1eddi ch\u01a1i s\u1ebd ph\u1ea3i ch\u1ecdn xi\u00ean 4, xi\u00ean 8, xi\u00ean 10 v\u00e0 n\u1ebfu c\u00f3 th\u00ec c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec:<\/p>\n
\n- \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/li>\n
- C\u1ea3 8 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 7.<\/li>\n
- 10 con c\u00f9ng tr\u01b0\u1ee3t th\u00ec 1 \u0103n 10.<\/li>\n<\/ul>\n
X\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 theo c\u00e1ch xi\u00ean 4, xi\u00ean 8 hay xi\u00ean 10 s\u1ebd cho ta bi\u1ebft nh\u1eefng c\u01a1 h\u1ed9i ki\u1ebfm ti\u1ec1n, cho n\u00ean ch\u00fang ta c\u1ea7n l\u00e0m r\u00f5 con s\u1ed1 n\u00e0y.<\/p>\n
V\u00e0 x\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t c\u1ee7a 1 con l\u00e0 78%, tuy l\u00f4 tr\u01b0\u1ee3t c\u00f3 27 gi\u1ea3i nh\u01b0ng ch\u1ec9 c\u00f3 b\u00ecnh qu\u00e2n 21,5 \u2013 22 s\u1ed1 kh\u00e1c nhau => trong 100 s\u1ed1 th\u00ec c\u00f3 \u0111\u1ebfn 78 s\u1ed1 l\u00e0 tr\u01b0\u1ee3t => x\u00e1c su\u1ea5t \u0111\u1ec3 ch\u1ecdn 1 l\u00f4 tr\u01b0\u1ee3t = 78%. T\u1eeb \u0111\u00f3 ta c\u00f3 th\u1ec3 suy ra.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 4: 0,78\u00d70,78\u00d70,78\u00d70,78 = 0,37, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 37% khi c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/p>\n
L\u01b0u \u00fd<\/strong>: x\u00e1c xu\u1ea5t \u0111\u00e1nh b\u1ea1ch th\u1ee7 tr\u00fang 1 con l\u00f4 l\u00e0 22%, nh\u01b0ng Ti\u1ec1n thu v\u1ec1 = 3,5 Ti\u1ec1n chi ra, ch\u1ee9 kh\u00f4ng ph\u1ea3i ch\u1ec9 \u0103n 2 l\u1ea7n. C\u00e1c b\u1ea1n c\u0169ng n\u00ean ph\u00e2n bi\u1ec7t x\u00e1c su\u1ea5t tr\u00fang v\u1edbi t\u1ef7 l\u1ec7 \u0103n ti\u1ec1n.<\/p>\n\u2013 L\u00f4 tr\u01b0\u1ee3t xi\u00ean 8: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 = 0,14, t\u01b0\u01a1ng \u1ee9ng v\u1eady x\u00e1c su\u1ea5t \u0103n l\u00e0 14% , gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 10: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 x0,78\u00d70,78 = 0,083, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 8,3%, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n
X\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 theo c\u00e1ch xi\u00ean 4, xi\u00ean 8 hay xi\u00ean 10 s\u1ebd cho ta bi\u1ebft nh\u1eefng c\u01a1 h\u1ed9i ki\u1ebfm ti\u1ec1n, cho n\u00ean ch\u00fang ta c\u1ea7n l\u00e0m r\u00f5 con s\u1ed1 n\u00e0y.<\/p>\n
V\u00e0 x\u00e1c su\u1ea5t c\u1ee7a \u0111\u00e1nh l\u00f4 tr\u01b0\u1ee3t c\u1ee7a 1 con l\u00e0 78%, tuy l\u00f4 tr\u01b0\u1ee3t c\u00f3 27 gi\u1ea3i nh\u01b0ng ch\u1ec9 c\u00f3 b\u00ecnh qu\u00e2n 21,5 \u2013 22 s\u1ed1 kh\u00e1c nhau => trong 100 s\u1ed1 th\u00ec c\u00f3 \u0111\u1ebfn 78 s\u1ed1 l\u00e0 tr\u01b0\u1ee3t => x\u00e1c su\u1ea5t \u0111\u1ec3 ch\u1ecdn 1 l\u00f4 tr\u01b0\u1ee3t = 78%. T\u1eeb \u0111\u00f3 ta c\u00f3 th\u1ec3 suy ra.<\/p>\n
\u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 4: 0,78\u00d70,78\u00d70,78\u00d70,78 = 0,37, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 37% khi c\u1ea3 4 con c\u00f9ng tr\u01b0\u1ee3t, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 2 ti\u1ec1n.<\/p>\n
L\u01b0u \u00fd<\/strong>: x\u00e1c xu\u1ea5t \u0111\u00e1nh b\u1ea1ch th\u1ee7 tr\u00fang 1 con l\u00f4 l\u00e0 22%, nh\u01b0ng Ti\u1ec1n thu v\u1ec1 = 3,5 Ti\u1ec1n chi ra, ch\u1ee9 kh\u00f4ng ph\u1ea3i ch\u1ec9 \u0103n 2 l\u1ea7n. C\u00e1c b\u1ea1n c\u0169ng n\u00ean ph\u00e2n bi\u1ec7t x\u00e1c su\u1ea5t tr\u00fang v\u1edbi t\u1ef7 l\u1ec7 \u0103n ti\u1ec1n.<\/p>\n \u2013 L\u00f4 tr\u01b0\u1ee3t xi\u00ean 8: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 = 0,14, t\u01b0\u01a1ng \u1ee9ng v\u1eady x\u00e1c su\u1ea5t \u0103n l\u00e0 14% , gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n \u2013 L\u00f4 tr\u01b0\u1ee3t c\u1ee7a xi\u00ean 10: 0,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78\u00d70,78 x0,78\u00d70,78 = 0,083, t\u01b0\u01a1ng \u1ee9ng x\u00e1c su\u1ea5t \u0103n l\u00e0 8,3%, gi\u00e1 tr\u1ecb l\u00e0 \u0111\u1eb7t 1 ti\u1ec1n \u0103n 7 ti\u1ec1n.<\/p>\n